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11 Visitor Messages

  1. View Conversation
    Your code:
    Code:
    (((coordinate >> 3) / 8) << 3) * 8
    simpler:
    Code:
    (((coordinate >> 3) >> 3) << 3) << 3
    simplest:
    Code:
    (coordinate >> 6) << 6
    Divides by 64, then multiplies by 64, which clears the last 6 bits of coordinate, getting the highest number that is divisible by 64 that is less than or equal to coordinate.

    It's the same thing as
    Code:
    (coordinate / 64) * 64
    and
    Code:
    coordinate & ~63
    But multiply and divide by powers of 2 is much slower than bit shifting.
  2. View Conversation
    skype?
  3. View Conversation
    lol.
  4. View Conversation
    I'm ok thanks. I have been on msn quite a bit. Everytime I'm on I never saw you online. I'm driving now anyway so won't be on msn that offen. When I'm on it be in the evenings for me. Talk soon!
  5. View Conversation
    Hello m8!
  6. View Conversation
    lol@your signature
  7. View Conversation
    Rs2d? Where can i find it;D
  8. View Conversation
    @ one of your threads(cbf to link)
    instead of a while look checking available()
    just use in.read()
    it will block the thread until data is received
  9. Hehehe
  10. View Conversation
    Errr... Lol
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